- 1 Need of Van der Waals Equation
- 2 Compressibility factor (Z)
- 3 Derivation of Van der Waals Equation
- 4 Units of Van der Waals Equation Constants(a,b)
- 5 Significance of Van der Waals Equation
- 6 Behaviour of Real Gas On the Basis of Van der Waals Equation
- 7 Behaviour of hydrogen and helium: Van der Waals Equation
Van der Waal (1873) suggested two corrections in an ideal gas equation(PV = nRT) so that it can also explain the behaviour of real gases.Hence the equation obtained by applying the two corrections to the usual gas equation is known as Van der Waals equation.
Must Read: Ideal gas equation.
Need of Van der Waals Equation
Real gases deviate from ideal behaviour because of the following two faulty assumptions of the kinetic theory.
(i) The actual volume occupied by molecules is negligible as compared to the total volume of the gas.
(ii) The forces of attraction and repulsion between molecules of the gas are negligible.
The extent of deviation of a real gas from ideal behaviour is expressed in terms of compressibility factor (z).
Compressibility factor (Z)
Thus greater is the departure of z from unity, more is the deviation from ideal behaviour.Thus, when
(i) Z=1, the gas is ideal. In the case of N2, the value of Z is close to 1 at 50°C. This temperature at which a real gas behaves like an ideal gas is called Boyle’s temperature or Boyle’s point.
(ii) Z>1 the gas is less compressible.
(iii) When the value of Z is less than 1 (Z<1) the gas is more compressible.
Hence, suitable corrections must be applied to the ideal gas equation so that it can also explain the behaviour of real gases.
Derivation of Van der Waals Equation
Van der Waals equation is obeyed by the real gases over a wide range of temperatures and pressures.
Corrected (ideal) volume = (V – b)
where b is the effective volume of the molecules. The constant b is also called co-volume or excluded volume. The excluded volume for n molecules of gas = 4nVm, i.e. it is 4 time the actual volume occupied by a molecule (Vm).
b = 4 × volume of a single molecule(6.023 × 1023 ×(4/3)r3,)
Pressure Correction(intermolecular attraction correction).
Corrected (ideal) pressure = P + p.
where p is the inward force exerted on molecules about to strike the wall.
where ‘a’ is a proportionality constant, called the coefficient of attraction; its value depends upon the nature of the gas.
Substituting the values of corrected pressure and corrected volume in the ideal gas equation, PV = RT, we have
The equation is known as van der Waal’s equation. The constants a and b are called van der Waal’s constants and their values depend upon the nature of the gas and independent of the temperature and pressure.
Refer to the video for Gas laws and Van der Waals Equation
Units of Van der Waals Equation Constants(a,b)
a and b depend on the units in which P and V are expressed.
Thus if pressure is expressed in atmospheres and volume in litres, the units of a will be atmosphere litre2 mol-2 or atm dm6 mol-2 or Nm4 mol-2.
Units of b. In the van der Waal’s equation, b is the effective volume occupied by molecules present in one mole of the gas. Hence the units of b are same as that of volume, i.e. litre mol-1 or m3 mol-1.
Significance of Van der Waals Equation
(i) The value of a is an indirect measure of the magnitude of attractive forces between the molecules. Greater is the value of a, more easily the gas liquefied. Thus the easily liquefiable gases (like SO2 > NH3 > H2S > CO2) have high values of a than the permanent gases (like N2, O2, H2 and He).
(ii) The value of b gives an idea about the effective size of gas molecules. Greater is the value of b, larger is the size and smaller is the compressible volume. As b is the effective volume of the gas molecules, the constant value of b for any gas over a wide range of temperature and pressure indicates that the gas molecules are incompressible.
Behaviour of Real Gas On the Basis of Van der Waals Equation
Unlike ideal gas equation, the van der Waals equation explains the behaviour of real gases under different conditions of temperature and pressure.
At low pressures
At low pressures, volume V is very large and hence the correction term b (a constant of small value) can be neglected in comparison to very large value of V. Thus the van der Waals equation for 1 mole of a gas, i.e.,
At extremely low pressure
Since V is very large, the value of a/V is very small and hence can be ignored. Consequently, at very low pressures, the van der Waals equation is reduced to ideal gas equation, i.e.,
This explains why at extremely low pressures, the real gases obey the ideal gas equation.
shows that PV is less than RT by an amount equal to a/V. As pressure increases, V decreases, as a/V increases and ultimately PV becomes smaller and smaller. This explains the dip in the isotherms of most of the gases (e.g., CO and CH4).
At high pressures
At high pressures, volume V is quite small and hence the term b cannot be neglected in comparison to V Secondly, under these conditions although the term as a/V2 is quite large, it is so small in comparison to high-pressure P that it can be neglected. Thus the van der Waals equation is reduced to
- P(V – b) = RT
- PV – Pb = RT
- PV = RT + Pb
Thus PV is greater than RT by an amount equal to Pb. As the pressure increases, the factor Pb increases and hence PV increases. This explains why the value of PV after reaching a minimum, increases with the further increase of pressure.
At high temperatures
At any given pressure, if the temperature is sufficiently high, V is very large and hence the terms a/V2 and b can be neglected as in case (i) and thus the van der Waals equation reduces to PV = RT. This explains why the real gases behave like an ideal gas at high temperatures.
At low temperatures.
At low temperatures both P and V are small, hence both pressure and Volume corrections are appreciable, with the result the deviations are more pronounced.
Behaviour of hydrogen and helium: Van der Waals Equation
Since hydrogen and helium have very small masses, the intermolecular forces of attraction are extremely small even at low pressures. In other words, the factor as V is negligible at all pressures. Hence the van der Waals equation is reduced to
- P(V – b) = RT
- PV = RT + Pb
This explains why hydrogen and helium show positive deviations only with an increase in the value of P.
This is Van der Waals Equation.
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