# Boyle’s Law Equation – Examples – Formula & Definition, Explanation

At the end of the Article, you will able to describe what exactly Boyle’s law is? Along with Boyle’s Law Equation – Examples – Formula & Definition, Explanation. Let’s start discussing it one by one.

## Boyle’s Law Equation

For a gas, pressure and volume are inversely proportional. If you keep Temperature and amount of gas Constant. Then,

• As the pressure on a gas goes up, its volume goes down. (See Situation B)
• As the volume of a gas occupies goes up, its pressure goes down. (See Situation C)

If you exert pressure on a gas you can compress it. You can easily make it take up less space.

### Boyle’s Law Equation Explanation

Imagine a hard container that measures how many times gas particles bang against the sides. The more the gas particles bang against the sides, the higher the gas pressure on the container.

If you make the container smaller, you compress. The gas the particles of gas will run into the sides more often per second so that means higher pressure.

 Pressure ↑ Volume ↓

If you keep the number of gas particles constant but you make the size of the container bigger. There will be fewer collisions per second with the sides that indicates lower pressure.

 Pressure ↓ Volume ↑

### Boyle’s Law Equation Definition

Robert Boyle stated the inverse relationship between pressure and volume as a gas law. Boyle’s law says that for a given amount of gas, at a fixed temperature, pressure and volume are inversely proportional.

P ∝ 1/V.

You can write this mathematically as

P = k/V

• Where P equals pressure.
• V equals volume and
• K is a proportionality constant.

We can rearrange this equation. So it reads

• PV = K
• or
• The product of pressure and volume is a constant, K.

Very often Boyle’s law is used to compare two situations a before and an after.

In that case, you can say P1V1 =K and P2V2 =K

So you can write Boyle’s law as,

P1V1 =P2V2

### Boyle’s Law Equation Examples

Example 1: A tire with a volume of 11.41 L reads 44 psi (pounds per square inch) on the tire gauge. What is the new tire pressure if you compress the tire and its new volume is 10.6 L?

Write out Boyle’s Law, what we know. This is one of those “before and after” situations, so we write

P1V1 =P2V2

P2 = 47.36 psi

Here’s another example.

Example 2: A syringe has a volume of 10.0 ccs (or 10 cubic centimeters). The pressure is 1.0 atm. If you plug the end so no gas can escape, and push the plunger down, what must the final volume be to change the pressure to 3.5 atm?